Syntax

#include <string.h>
char *strcpy(char *string1, const char *string2);

strcpy copies string2, including the ending null character, to the location specified by string1.

strcpy operates on null-terminated strings. The string arguments to the function should contain a null character (\0) marking the end of the string. No length checking is performed. You should not use a literal string for a string1 value, although string2 may be a literal string.

strcpy returns a pointer to the copied string (string1.).

This example copies the contents of source to destination.

#include <stdio.h>
#include <string.h>

#define  SIZE          40

int main(void)
{
   char source[SIZE] = "123456789";
   char source1[SIZE] = "123456789";
   char destination[SIZE] = "abcdefg";
   char destination1[SIZE] = "abcdefg";
   char *return_string;
   int index = 5;

   /* This is how strcpy works                                                */

   printf("destination is originally = '%s'\n", destination);
   return_string = strcpy(destination, source);
   printf("After strcpy, destination becomes '%s'\n\n", destination);

   /* This is how strncpy works                                               */

   printf("destination1 is originally = '%s'\n", destination1);
   return_string = strncpy(destination1, source1, index);
   printf("After strncpy, destination1 becomes '%s'\n", destination1);
   return 0;

   /****************************************************************************
      The output should be:

      destination is originally = 'abcdefg'
      After strcpy, destination becomes '123456789'

      destination1 is originally = 'abcdefg'
      After strncpy, destination1 becomes '12345fg'
   ****************************************************************************/
}

• strcat
  
• strdup
  
• strncpy
  
• wcscpy
  
• wcsncpy

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